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Question

If a1 and a2 be the coefficients of x4 and of x6 and (1+x)10 respectively, then

A
a1=a2
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B
2a1=a2
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C
a1=4a2
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D
a1=2a2
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Solution

The correct option is D a1=a2
For the above binomial expansion (1+x)10
Tr+1=10Crxr

Therefore the coefficient of x4 will be
10C4=a1

Similarly
coefficient of x6 will be
a2=10C6

Now by the property of binomial coefficient
nCr=nCnr

Therefore
10C4=10C104
=10C6

Therefore, a1=a2

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