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Question

If a2+4b2=12ab, then log(a + 2b) is
  1. 12[log a+log b+4 log 2]
  2. 12[log a+log blog 2]
  3. 12[log alog b+4 log 2]
  4. loga2+logb2+log 2


Solution

The correct option is A 12[log a+log b+4 log 2]
a2+4b2=12aba2+4b2+4ab=16ab(a+2b)2=16ab
2log(a+2b)=log 16+log a+log b
 log(a+2b)=12[log a+log b+4 log 2]

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