Question

If $a^2+\frac{1}{a^2}=102$, find the value of $a-\frac{1}{a}$

Answer 1

we have,

$\Rightarrow {(a-\frac{1}{a})}^2=a^2+\frac{1}{a^2}-2$

From Given, we have,

$\Rightarrow {(a-\frac{1}{a})}^2=102-2=100$

$\therefore a-\frac{1}{a}=10$