If A -45-Then- secA cotA -cosecA tanA -

Sec A=√(2) Cosec A=√(2) Tan A=1 Therefore, √(2) √(2)=0 ...

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Standard Values of Trigonometric Ratios

If A =45∘Then...

Question

If A= $45^{\circ}$

Then, secA cotA –cosecA tanA =__

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If A= $45^{\circ}$

Then, secA cotA –cosecA tanA =__

\frac{t a n A}{1 - c o t A} + \frac{c o t A}{1 - t a n A} = 1 + s e c A c o s e c A

t a n A = \frac{4}{3}

\frac{c o s e c A}{c o t A - s e c A}

- \frac{15}{m}

\frac{tan A}{1 - cot A} + \frac{cot A}{1 - tan A}

secA

cosecA + 1.

(1 + c o t A - c o s e c A) (1 + t a n A + s e c A) = 2

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