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Question

If a and b are positive integer such that N=(a+ib)3107i is a positive integer then find the value of N2.

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Solution

N=(a+ib)3107i=(a33ab2)+(b3+3a2b107)i
N is possible integer 3a2bb3=107
a=6,b=1 (trial & error solution)
N=a33ab2=633.6,21618=198N/2=99

1180045_876071_ans_5c06a6b33bf44af498b14d7a92e3c509.jpg

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