If A and B are standing at (2, 7) and (9, -1) respectively, how far is A from B?

\sqrt{93}

units

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\sqrt{113}

units

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\sqrt{73}

units

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\sqrt{57}

units

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Solution

The correct option is B $\sqrt{113}$ units
Given: A(2, 7) and B(9, -1)

The distance between two points $(x_{1}, y_{1}) and (x_{2}, y_{2})$ is $\sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}} .$

AB = $\sqrt{(9 - 2)^{2} + (- 1 - 7)^{2}}$
AB = $\sqrt{(7)^{2} + (- 8)^{2}}$
AB = $\sqrt{49 + 64}$
AB = $\sqrt{113}$ units

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If A and B are standing at (2, 7) and (9, -1) respectively, how far is A from B?

The correct option is B √113 unitsGiven: A(2, 7) and B(9, -1) The distance between two points (x1,y1) and (x2,y2) is √(x2−x1)2+(y2−y1)2. AB = √(9−2)2+(−1−7)2 AB = √(7)2+(−8)2 AB = √49+64 AB = √113 units ​​​​​​​