If ∠A and ∠B are supplementary angles and m∠B = (x + 20)^°, then what would be m∠A?

Open in App

Solution

Let the measure of the supplementary angle of ∠B be a.
(x + 20)^° + a = 180
∴ a = (160 − x)°
Hence, the measure of ∠A is (160 − x)°.

Suggest Corrections

Similar questions

∠ A

and

∠ B

are supplementary angles.

∠ A = x + 10^{o}

and

∠ B = x - 10^{o}

, find

∠ A

and

∠ B

Q. If A and B are two supplementary angles then

{sec}^{2} A - {tan}^{2} B =

___

Q. If 4∠A = 2∠B = ∠C, ∠A and ∠B are complementary angles and ∠B and ∠C are supplementary angles, then the measures of ∠A, ∠B and ∠C are, respectively

If ∠A = 2x and ∠B = 4x such that ∠A and ∠B are supplementary, then the value of x is:

(a) What are the three conditions that must be satisfied for two angles to be adjacent? [3 MARKS]

(b) In the given figure, \(\angle 1\) and \(\angle 2\) are supplementary angles. If \(\angle 1\) decreases, then \(\angle 2\) will _______ so that both the angles are still supplementary.

Join BYJU'S Learning Program

If ∠A and ∠B are supplementary angles and m∠B = (x + 20)°, then what would be m∠A?

Let the measure of the supplementary angle of ∠B be a. (x + 20)° + a = 180 ∴ a = (160 − x)° Hence, the measure of ∠A is (160 − x​)°.

If ∠A and ∠B are supplementary angles and m∠B = (x + 20)^°, then what would be m∠A?

Let the measure of the supplementary angle of ∠B be a.
(x + 20)^° + a = 180
∴ a = (160 − x)°
Hence, the measure of ∠A is (160 − x)°.