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Question

If α and β are the roots of the equation x2a(x+1)b=0, then (α+1)(β+1)=


A

b

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B

-b

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C

1-b

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D

b-1

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Solution

The correct option is C

1-b


Given equation x2a(x+1)b=0

x2axab ⇒ α + β = α, αβ = -(a + b)

Now (α+1)(β+1)=αβ+α+β+1=(a+b)+a+1=1b


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