Question

If `a' and `b' are whole numbers such that b > 1 and a${}^b$ = 144, what is the value of (a - 2)${}^{b+2}$ ?

• A. 100
• B. 1000
• C. 10000
• D. 0.01
• E. 0.0001

Answer 1

The correct option is C

10000

$\because$ 12${}^2$ = 144 $⟹$So, a = 12 & b =2

( a - 2)${}^{b+2}$ = (12 - 2)${}^{2+2}$ = 10${}^4$ = 10000