If 'a' and 'b' are zeroes of the polynomial f(t)=t^2-5t+3,then find the value of (a^3b^4)+(a^4b^3).

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0 < a < 1, b < 1

{tan}^{- 1} a + {tan}^{- 1} b = \frac{π}{4}

(a + b) - (\frac{a^{2} + b^{2}}{2}) + (\frac{a^{3} + b^{3}}{3}) - (\frac{a^{4} + b^{4}}{4}) + . . . .

a + b + c = 3

a^{2} + b^{2} + c^{2} = 6

a^{3} + b^{3} + c^{3} = 8

a^{4} + b^{4} + c^{4} = ?

\sqrt{a^{3} b^{4}} \sqrt[3]{a^{4} b^{3}}

= a^{2} b^{3} \cdot {\sqrt[6]{a}}^{5}

a_{1}, a_{2}, a_{3}, a_{4}

b_{1} = a_{1}, b_{2} = b_{1} + a_{2}, a_{3} = b_{2} + a_{3}

b_{4} = b_{3} + a_{4}

b_{1}, b_{2}, b_{3}, b_{4}

b_{1}, b_{2}, b_{3}, b_{4}

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If 'a' and 'b' are zeroes of the polynomial f(t)=t^2-5t+3,then find the value of (a^3*b^4)+(a^4*b^3).