If a = b(1+ct) & a = 1100, b = 1000 & t = 100, then the value of c is
1.01
0.001
0.1
0.01
1100=1000(1+100c)
(11/10) -1 = 100c = c=1/1000
If angular displacement of a particle is given by θ=a−bt+ct2, then find its angular velocity.
If a, b, c are positive real numbers such that a + b + c = 1 then the least value of (1+a)(1+b)(1+c)(1−a)(1−b)(1−c) is is
If 38 = a10 + b100 + c1000 find the value of a , b and c.