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Question

If a,b and c are unit vectors then |ab|2+|bc|2+|ca|2 does not exceed

A
4
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B
9
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C
8
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D
6
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Solution

The correct option is B 9
|ab|2+|bc|2+|ca|2
=2(a2+b2+c2)2(a.b+b.c+c.a)
=2×32(a.b+b.c+c.a)
=6{(a+b+c)2a2b2c2}
=9|a+b+c|29

Hence, option B.

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