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Question

If a+b+c=0 and |a|=3, |b|=4 and |c|=37, the angle between a and b is

A
π4
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B
π2
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C
π6
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D
π3
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Solution

The correct option is D π3
a+b+c=0a+b=c|a+b|2=|c|2|a|2+|b|2+2a.b=|c|29+16+2(3)(4)cos(a,b)=3724cos(a,b)=12cos(a,b)=12(a,b)=π3

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