Question

If $a+b+c=0$, the straight line $2ax+3by+4c=0$ passes through the fixed point

• A. $[2,\frac{4}{3}]$
• B. $(2,2)$
• C. $[\frac{4}{3},\frac{4}{3}]$
• D. $Suchpointdoesnotexist$

Answer 1

The correct option is A $[2,\frac{4}{3}]$

We have,

$a+b+c=0......\left(1\right)$

$2ax+3by+4c=0......\left(2\right)$

Now,

On multiplying by 4 in equation (1) and we get,

$4a+4b+4c=0......\left(3\right)$

From equation (2) and (3) to and we get,

$x=2,y=\frac{4}{3}$

Hence, this is the answer.