CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

If $$a+b+c=10$$ and $$a^2+b^2+c^2=36$$, then $$ab+bc+ca=$$________


A
136
loader
B
64
loader
C
32
loader
D
none of these
loader

Solution

The correct option is B $$32$$
We know, $$(a+b+c)^2=a^2+b^2+c^2+2ab+2bc+2ca$$
$$(10)^2=36+2(ab+bc+ca)$$
$$100-36=2(ab+bc+ca)$$
$$2(ab+bc+ca)=64$$
$$(ab+bc+ca)=32$$

Mathematics

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More



footer-image