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Question

If ab+c=5 and caabbc=7, then value of a2+b2+c2 is 


Solution

Given: 
ab+c=5 and caabbc=7
We know that,
(a+b+c)2=a2+b2+c2+2(ab+bc+ca)
Replacing bb, we get
(ab+c)2=a2+b2+c2+2(abbc+ca)25=a2+b2+c2+2×7a2+b2+c2=11

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