If a, b, c are in A.P. and a, x, b and b, y, c are in G.P. show that x2,b2,y2 are in A.P.
a, b, c are in A.P.
⇒b2=a+c ............(1)
a, x, b are in GP
⇒x2=ab ..............(2)
And b, y, c are in G.P.
⇒y2=bc ...............(3)
Now
2b2=x2+y2
=(ab)+(bc) [Using (2) and (3)]
2b2=b(a+c)
2b2=b(2b)
b22=2b2
LHS = RHS
⇒2b2=x2+y2
⇒x2,b2,y2 are in A.P.