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Question

If a, b, c are in A.P. and a, x, b and b, y, c are in G.P. show that x2,b2,y2 are in A.P.

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Solution

a, b, c are in A.P.

b2=a+c ............(1)

a, x, b are in GP

x2=ab ..............(2)

And b, y, c are in G.P.

y2=bc ...............(3)

Now

2b2=x2+y2

=(ab)+(bc) [Using (2) and (3)]

2b2=b(a+c)

2b2=b(2b)

b22=2b2

LHS = RHS

2b2=x2+y2

x2,b2,y2 are in A.P.


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