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Question

If a,b,c are integers and b2=4(ac+5d2),dN, then roots of the quadratic equation ax2+bx+c=0

A
Irrational
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B
Rational & different
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C
Complex conjugate
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D
Rational & equal
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Solution

The correct option is C Irrational
b2=4(ac+5d2)
D=b24ac
=4(ac+5d2)4ac
=4ac+20d24ac
=20d2
Now, x=b±D2a
=b±20d22a
=b±25d2a
Therefore, roots of the given quadratic equation are irrational

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