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Question

If a,b,c are positive such that ab2c3=64 then least value of (1a+2b+3c) is

A
6
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B
2
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C
3
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D
32
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Solution

The correct option is D 3
Given numbers a,b,c such that ab2c3=64
Since,G.M.H.M.
(a.b.b.c.c.c)1661a+1b+1b+1c+1c+1c
(64)1/661a+2b+3c
1a+2b+3c3

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