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Question

If A, B, C are represented by 3 + 4i, 5 - 2i , -1 + 16i, then A, B, C are
[RPET 1986]

A
Collinear
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B

Vertices of equilateral triangle

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C

Vertices of isosceles triangle

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D

Vertices of right angled triangle

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Solution

The correct option is A Collinear
Given that points are A(3 + 4i), B(5 - 2i) and C(-1 + 16i)

Area of triangle = 12∣ ∣x1y11x2y21x3y31∣ ∣=12∣ ∣3415211161∣ ∣=0
Hence points are collinear.


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