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Question

If a, b, c are roots of the equation x3+2x2+1=0, then ∣ ∣abcbcacab∣ ∣=

A
2
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B
8
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C
- 8
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Solution

The correct option is B 8
∣ ∣abcbcacab∣ ∣=3abca3b3c3
=(a+b+c)((a+b+c)23(ab+bc+ca))
=(2)((2)23×0)=8

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