If a- b- c are three non-coplanar vectors such that a - b - c - - d and b - c - d - - a then a- b- c-d is equal to

The correct option is A 0 a + b + c =α (β a b c) ⇒ #160; (1 αβ )a+(1+α )b+(1+α )c=0 ⇒ 1 =αβ and α = 1 (a, b, c are non coplanar ...

If a, b, c ...

Question

If $a, b, c$ are three non-coplanar vectors such that $a + b + c = α d$ and $b + c + d = β a$ then $a + b + c + d$ is equal to

0

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α a

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β b

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(α + β) c

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a + b + c = α d

b + c + d = β a

a + b + c + d

a + b + c = α d, b + c + d = β a

a + b + c + d = 0

\to a, \to b, \to c

\to a + \to b + \to c = α \to d

\to b + \to c + \to d = β \to a

\to a + \to b + \to c + \to d =

a + b + c = α d a n d b + c + d = β a

a + b + c + d = 0

\vec{a,} \vec{b,} \vec{c}

\vec{d} \cdot \vec{a} = \vec{d} \cdot \vec{b} = \vec{d} \cdot \vec{c} = 0,

\vec{d}