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Question

If a:b=c:d=e:f=1:2, then (3a+5c+7e):(3b+5d+7f) is equal to:

A
8:7
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B
2:1
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C
1:4
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D
1:2
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Solution

The correct option is D 1:2
Given, ab=cd=ef=12
b=2a;d=2c;f=2e

3a+5c+7e3b+5d+7f= 3a+5c+7e3×2a+5×2c+7×2e

3a+5c+7e3×2a+5×2c+7×2e=3a+5c+7e2(3a+5c+7e) =12

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