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Question

If a,b,c R, then roots of the quadratic equation
x20.2ax+a2b2c2=0 are

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Solution

x20.2ax+a2b2c2=0

10x22ax+10a210b210c2=0

We have a formula for solving quadratic equation ax2+bx+c=0 is

x1,2=b±b24ac2a

x=(2a)±(2a)2410(10a210b210c2)210

x=a±100b2+100c299a210

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