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Byju's Answer
Standard XII
Mathematics
Differentiation of Inverse Trigonometric Functions
If A+B+C= π ...
Question
If A+B+C=
π
, then
s
e
c
A
(
c
o
s
B
c
o
s
C
−
s
i
n
B
s
i
n
C
)
is equal to__________
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Solution
Given,
A
+
B
+
C
=
π
∴
B
+
C
=
π
−
A
s
e
c
A
(
c
o
s
B
⋅
c
o
s
C
−
s
i
n
B
⋅
s
i
n
C
)
=
s
e
c
A
⋅
c
o
s
(
B
+
C
)
.................................
(
∵
cos
(
c
+
d
)
=
cos
c
⋅
cos
d
−
sin
c
⋅
sin
d
)
=
s
e
c
A
⋅
c
o
s
(
π
−
A
)
=
s
e
c
A
⋅
(
−
c
o
s
A
)
=
−
1
The answer is
−
1
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0
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