Question

If a block of mass $2kg$ is displaced by $10m$ towards right by the application of force $F$, as shown in fig. then work done by force $F$ is

• A. $20J$
• B. $40J$
• C. $60J$
• D. $80J$

Answer 1

The correct option is D $80J$

If a block of mass $M+2kg$

Displacement $d=10m$

Force $=F$

Work done $=F\times d\cos \theta (\because \theta =37°)=ma\times d\cos 37°=10\times 10\cos 37°=100\cos 37°=78.8=80J$