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Question

If a body is thrown up with an initial velocity u and covers a maximum height of h, then h is equal to u22g.


  1. u2/2g

  2. u/2g


Solution

The correct option is A

u2/2g


Using equation v2 = u2+2as
Here a=g
[ acceleration due to gravity is acting opposite to the direction of motion]
s=h 

At highest point, v=0

0=u22gh

h=u22g

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