If a body is thrown vertically upward and rises to a height of 10 m, then time taken by the body to reach the highest point is

1.043 s

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

1.43 s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1.024 s

No worries! We‘ve got your back. Try BYJU‘S free classes today!

None of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 1.043 s
From $v = u - g t$
$0 = 10 - 9.8 t$
$\Rightarrow u^{2} = 196$
$\Rightarrow t = \frac{10}{9.8} = 1.043 s e c$

Suggest Corrections

Similar questions

Q. A body is thrown vertically upwards and rises to a height of 10 m. The time taken by the body to reach the highest point is (g = 9.8

m / s^{2}

)

Q. A body is thrown vertically upwards and rises to a height of

10 m

. The time taken by the body to reach the highest point is

An object is thrown vertically upwards and rises to a height of $10 c m$ . Calculate
(i) the velocity with which the object was thrown upwards and
(ii) the time taken by the object to reach the highest point.

A body is thrown vertically upwards. If air resistance is to be taken into account, then the time during which the body rises is

Q. A body is thrown vertically upwards and rises to a height of 10 m. The velocity with which the body was thrown upwards is

(g = 9.8 m / s^{2})

Join BYJU'S Learning Program

If a body is thrown vertically upward and rises to a height of 10 m, then time taken by the body to reach the highest point is

The correct option is A 1.043 sFrom v=u−gt0=10−9.8t⇒u2=196⇒t=109.8=1.043sec

The correct option is A 1.043 s
From $v = u - g t$
$0 = 10 - 9.8 t$
$\Rightarrow u^{2} = 196$
$\Rightarrow t = \frac{10}{9.8} = 1.043 s e c$