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# If a bomb at rest explodes and splits into two equal fragments, the fragments will move in: (a) One direction and with equal velocities. (b) Opposite directions with different velocities. (c) One direction with different velocities. (d) Opposite directions with equal velocities. [1 mark]

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## Solution: Correct Option: Option (d) Let the mass of the bomb be M. ∴The masses of two equal fragments of the bomb is M2 each. Let U be the initial velocity of the bomb and v1 and v2 be the velocity of the fragments after explosion. As there is no external force applied in this case, ∴ momentum before explosion = momentum after explosion. i.e, MU=M2 v1+M2 v2 As bomb was at rest initially, MU=0 we have, M2 v1+M2 v2 will also be equal to zero. ∴ M2 v1+M2 v2=0 M2 v1=−M2 v2 ⇒ v1=−v2 This means the fragments will move in opposite directions with equal velocity.  Suggest Corrections  0      Similar questions  Related Videos   Conservation of Momentum
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