If a car travels first 40km at speed of 20km/h and next 80km at a speed of 40km/h. What is the average speed of car for entire journey?

30 km/hr

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

45 km/hr

No worries! We‘ve got your back. Try BYJU‘S free classes today!

35 km/hr

No worries! We‘ve got your back. Try BYJU‘S free classes today!

45 km/hr

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
30 km/hr

$A v e r a g e s p e e d = \frac{t o t a l d i s t a n c e}{t o t a l t i m e} = \frac{40 + 80}{\frac{40}{20} + \frac{80}{40}} = 30 k m / h r$

Suggest Corrections

Similar questions

If a car travels a distance of 120 km with a speed of 80 km/h and returns with a speed of 60 km/h. Calculate the average velocity for the entire journey.

A train travels 40 km at a uniform speed of $30 k m / h r$ . Its average speed after travelling another 40 km is $45 k m / h r$ for the whole journey. Find its speed in the second half of the journey.

Q. A car travels first 30km at a speed of 40km/hr and next 30km at a speed of 20km/hr. Find the average speed of the car

What is the relative speed when a train with a speed of 40 km/hr crosses a car traveling at the speed of 70 km/hr moving in the same direction.

a) A train travels a distance with a speed of 40 km/h and returns with a speed of 60 km/h. Calculate the average speed of the train.

b) On a 60 km track, a train travels the first 30 km at a uniform speed of 30 km/h. How fast must a train travel the next 30 km so that the average speed is 40 km/hr for the entire trip?

Join BYJU'S Learning Program

If a car travels first 40km at speed of 20km/h and next 80km at a speed of 40km/h. What is the average speed of car for entire journey?

The correct option is A 30 km/hr Average speed=total distancetotal time=40+804020+8040=30 km/hr

The correct option is A
30 km/hr

$A v e r a g e s p e e d = \frac{t o t a l d i s t a n c e}{t o t a l t i m e} = \frac{40 + 80}{\frac{40}{20} + \frac{80}{40}} = 30 k m / h r$