If a certain toy store-s revenue in November was 25 of its revenue in December and its revenue in January was 14 of its revenue in November- then the store-s revenue in December was how many times the average arithmetic mean of its revenues in November and January-

The correct option is E 4 Let the revenue in December be x Given that revenue in November is 25 of its revenue in December.Therefore, revenue i ...

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Standard IX

Mathematics

Mean of Ungrouped Frequency Distribution by Simple Method

If a certain ...

Question

If a certain toy store's revenue in November was $\frac{2}{5}$ of its revenue in December and its revenue in January was $\frac{1}{4}$ of its revenue in November, then the store's revenue in December was how many times the average (arithmetic mean) of its revenues in November and January?

\frac{1}{4}

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\frac{1}{2}

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\frac{2}{3}

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2

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4

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Solution

The correct option is E $4$
Let the revenue in December be $x$

Given that revenue in November is $\frac{2}{5}$ of its revenue in December.

Therefore, revenue in November is $\frac{2}{5} x$

Given that revenue in January is $\frac{1}{4}$ of its revenue in November.

Therefore, revenue in January is $\frac{1}{4} (\frac{2}{5} x) = \frac{1}{10} x$

Average of revenues in November and January is $\frac{\frac{2}{5} x + \frac{1}{10} x}{2}$

$= \frac{4 + 1}{2 \times 10} x = \frac{1}{4} x = \frac{1}{4} (revenue in December)$

$⟹ revenue in December = 4 (average)$

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If a certain toy store's revenue in November was 25 of its revenue in December and its revenue in January was 14 of its revenue in November, then the store's revenue in December was how many times the average (arithmetic mean) of its revenues in November and January?

If a certain toy store's revenue in November was $\frac{2}{5}$ of its revenue in December and its revenue in January was $\frac{1}{4}$ of its revenue in November, then the store's revenue in December was how many times the average (arithmetic mean) of its revenues in November and January?