Question

If a coin is tossed four times, what is the probability of getting exactly two heads and two tails?

Answer 1

The favourable outcomes for the event are HHTT, HTHT, HTTH, THHT, THTH and TTHH. That’s 6 out of 16 outcomes. Hence, the probability is $\frac{6}{16}$ = $\frac{3}{8}$.