Question

If a coin is tossed twice, what are the chances that one toss will land heads-up and the other will land tails-up?

• A. One in three
• B. One in two
• C. Two in five
• D. Two to one

Answer 1

Answer: (B)

One in two

When a coin is tossed twice, the pair of possible outcomes are $(H,H);(H,T);(T,H);(T,T)$.
Of these, the times when one toss will land heads-up and the other will land tails-up $=2$.
Hence, required chances $=\frac{Requiredoutput}{Totaloutputs}=\frac{2}{4}=\frac{1}{2}$.