If a colour blond man marries a woman who is homozygous for normal colour vision, the probability of their son being colour blind is

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0.5

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0.75

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Solution

The correct option is B 0
Genotype of colour blind man = XcY
Genotype of normal female = XX

Thus, the cross between these two individuals will give the possible combinations and from the Punnett Square it is evident that none of the sons are victims of the disease. So none of them will be colour blind.

Male/Female Xc Y
X XXc XY
X XXc XY
So the correct option is '0.0'.

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