Question

If $A+D>C+E,C+D=2B$ and $B+E=C+D$, it necessarily follows that

• A. $A+B>2D$
• B. $B+D>C+E$
• C. $A+D>B+E$
• D. $A+D>B+C$

Answer 1

The correct option is D $A+D>B+C$

$A+D>C+E$
$\Rightarrow A+D>(2B-D)+E$ ...$(\because C+D=2B)$
$\Rightarrow A+D>(B+E)+(B-D)$
$\Rightarrow A+D>(C+D)+(B-D)$
$\Rightarrow A+D>B+C$.