If a+1b=1, and b+1c=1, then c+1a=k, what is the value of 100k?
200
100
100b
200b
None of these
1a=bb−1 Putting in c+1a=k, we get bc−c+bb−1=k Also, bc=c−1
Thus, on simplifying we get k=1. So 100k=100
If 1b−a+1b−c=1a+1c, then a,b,c, are in
If in a triangle ABC, ∠C=60o, then 1a+c+1b+c= [IIT 1975]