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Question

If A is a square matrix of order 3 such that |A|=2 then (adj A1)1 is

A
1
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B
2
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C
4
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D
8
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Solution

The correct option is C 4
we know,
adj(A1)=(adjA)1
(adjA1)1=((adjA)1)1=adj A
Also, |adjA|=(det(A))n1
Given, det(A) = 2, n = 3
|(adj A1)1|=(2)31
=22=4

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