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Question

If A is an acute angle in a right â–³ABC, right angled at B, then the value of sinA+cosA is:

A
equal to one
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B
greater than one
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C
less than one
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D
equal to two
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Solution

The correct option is C greater than one
ABC is a right angled triangle and right angle at B
sinA=BCAC, cosA=ABAC
sinA+cosA=BCAC+ABAC
=BC+ABAC
[We know that sum of two sides of a triangle is greater than the third side]
sinA+cosA>ACAC=1
Hence, sinA+cosA>1

481711_324759_ans_246f82e3ecb0428ab838adbe1e1c1709.png

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