Question

If $A$ is the areal velocity of planet of mass $M$. its angular momentum is

• A. $M$
• B. $2MA$
• C. $A^{2}M$
• D. $A{M}^2$

Answer 1

The correct option is B $2MA$

Areal Velocity, $A=\frac{Areasweptbyradiusvector}{Timetaken}=\frac{\pi R^2}{T}$

Time period, $T=\frac{2\pi }{\omega }$

Now, $A=\frac{R^2\omega }{2}$

$\omega =\frac{2A}{R^2}$

Angular momentum, $L=I\omega =M{R}^2\times \frac{2A}{R^2}=2MA$