If A-x-fx-0 and B-x-gx-0 then A - B will be the set of roots of the equation

The correct option is D none A={x:f(x)=0} A∪ B will be the set of root of the equation. B={x:g(x)=0} f(x)g(x)=0 possible g(x)≠ 0 and ...

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Byju's Answer

Standard XII

Mathematics

Monotonically Increasing Functions

If A=x:fx=0...

Question

If $A = {x : f (x) = 0}$ and $B = {x : g (x) = 0}$ then $A \cap B$ will be the set of roots of the equation

\frac{f (x)}{g (x)} = 0

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\frac{g (x)}{f (x)} = 0

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[f (x)]^{2} + [g (x)]^{2} = 0

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Solution

The correct option is D $n o n e$
$A = {x : f (x) = 0} A \cup B$ will be the set of root of the equation.
$B = {x : g (x) = 0}$
$\frac{f (x)}{g (x)} = 0$ possible $g (x) \neq 0$
and given that $β = {x : g (x) = 0}$
$A$ option is not possible.

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If A={x:f(x)=0} and B={x:g(x)=0} then A∩B will be the set of roots of the equation

The correct option is D noneA={x:f(x)=0}A∪B will be the set of root of the equation.B={x:g(x)=0}f(x)g(x)=0 possible g(x)≠0and given that β={x:g(x)=0}A option is not possible.

If $A = {x : f (x) = 0}$ and $B = {x : g (x) = 0}$ then $A \cap B$ will be the set of roots of the equation

The correct option is D $n o n e$
$A = {x : f (x) = 0} A \cup B$ will be the set of root of the equation.
$B = {x : g (x) = 0}$
$\frac{f (x)}{g (x)} = 0$ possible $g (x) \neq 0$
and given that $β = {x : g (x) = 0}$
$A$ option is not possible.