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Question

If A=diag(1,1,2) and B=diag(2,3,1) then 3A+4B=diag(a,b,c). Then abc=

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Solution

3A+4B=3diag(1,1,2)+4diag(2,3,1)
=diag(3,3,6)+diag(8,12,4) =diag(11,9,2)
abc=0

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