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There are 2n Non Perfect Square Numbers Between the Squares of the Numbers n and (n+1)

If a natural ...

Question

If a natural number 'm' can be expressed as $n^{2}$ , where n is a number, then 'm' is a square number.

decimal

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natural

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whole

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Solution

The correct option is B natural
If a natural number 'm' can be expressed as $n^{2}$ , where n is a natural number, then 'm' is a square number.

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Similar questions

If a natural number 'm' can be expressed as $n^{2}$ , where n is a ___ number, then 'm' is a square number.

If a natural number 'm' can be expressed as $n^{2}$ where n is a decimal number, then 'm' is a square number.

n^{2}

n^{2}

In general, if a natural number m can be expressed as $n^{2}$ , where n is also a natural number, then m is a __________.

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