Question

If a pair of dice is thrown once, then what is the probability of getting a sum of $8$

Answer 1

When a pair of dice is thrown,

$n\left(s\right)=6\times 6=36$

and,

$E=$ event of getting a sum of $8$

$=\left\{\right(2,6),(3,5),(4,4),(5,3),(6,2\left)\right\}$

$\therefore n\left(E\right)=5$

then,

$P\left(E\right)=\frac{n\left(E\right)}{n\left(S\right)}=\frac{5}{36}$