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Question

If a plane passes through the point (1,1,1) and is perpendicular to the line x13=y10=z14 then its perpendicular distance from the origin is


Your Answer
A
34
Your Answer
B
43
Correct Answer
C
75
Your Answer
D
1

Solution

The correct option is B 75
The d.r of the normal to the plane is(3,0,4) The equation of the plane is 3x + 0y + 4z + d = 0  since it passes through (1, 1, 1)  so; d = --7
Now distance of the plane3x+4z7=0 from (0, 0, 0)  is 732+42=75 units

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