If a proton and anti-proton come close to each other and annihilate, how much energy will be released?

1.5 \times 10^{- 10} J

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3 \times 10^{- 10} J

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4.5 \times 10^{- 10} J

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2 \times 10^{- 10} J

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Solution

The correct option is C $3 \times 10^{- 10} J$
Mass of proton $=$ mass of anti-proton
$= 1.67 \times 10^{- 27} k g = 1 a m u$
Energy equivalent to $1 a m u = 931 M e V$
So, energy equivalent to $2 a m u = 2 \times 931 M e V$
$= 1862 \times 10^{6} \times 1.6 \times 10^{- 19}$
$= 2.97 \times 10^{- 10} J$
$= 3 \times 10^{- 10} J$

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If a proton and anti-proton come close to each other and annihilate, how much energy will be released?

The correct option is C 3×10−10JMass of proton = mass of anti-proton =1.67×10−27kg=1amuEnergy equivalent to 1amu=931MeVSo, energy equivalent to 2amu=2×931MeV =1862×106×1.6×10−19 =2.97×10−10J =3×10−10J