CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

If a root of the equation ax2+bx+c=0 be reciprocal of the equation then ax2+bx+c=0, then


A

(ccaa)2=(bacb)(abbc).

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B

(bbaa)2=(cabc)(abbc).

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

(ccaa)2=(bacb)(abbc).

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

(cc+aa)2=(bacb)(abbc).

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A

(ccaa)2=(bacb)(abbc).


Let α be a root of first equation, then 1α be a root of second equation.

therefore aα2+bα+c=0 and a1α2+b1α+c=0 or cα2+bα+d=0

Hence α2babc=αccaa=1abbc

(ccaa)2=(bacb)(abbc).


flag
Suggest Corrections
thumbs-up
7
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Geometric Progression
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon