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Question

If a sample of $$MgBr_2$$ contains $$4\times 10^{20} Br^-$$ ions, then the number of $$Mg^{2+}$$ ions present in it is:


A
4×1020
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B
8×1020
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C
2×1020
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D
1×1020
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Solution

The correct option is D $$2 \times 10^{20}$$
correct answer: option 'C'

$$MgBr_2\rightarrow Mg^{2+} +2Br^-$$

Explanation: because the number of $$Mg^{2+}$$ ions are half of $$Br^-$$ ions. 

Therefore option 'C' is the correct answer

Chemistry

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