If a sample of water contains 68 ppm of Calcium Sulphate, what would be the hardness of the water?

200

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100

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136

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Solution

The correct option is B
50

Molar mass of $C a S O_{4}$ is $136 g m o l^{- 1}$
So 136 ppm $\equiv$ 100 (degree of hardness)

Now, 68 ppm $\equiv$ $\frac{100}{136} \times$ 68 = 50

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