CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon


Question

If a source of power 4 kW produces 1020 photon/second, the radiation belong to a part of the spectrum called, (h=6.6×1034Js )


A
x-rays
loader
B
UV-rays
loader
C
microwaves
loader
D
gamma-rays
loader

Solution

The correct option is A x-rays
power =nhvtP=(nt)hv4×103=1020×6.6×1034×vv=4×1036.6×1014=6×1016Hz
The obtained frequency lies in the band of X-rays

Physics

Suggest Corrections
thumbs-up
 
0


similar_icon
Similar questions
View More


similar_icon
People also searched for
View More



footer-image