If a star can convert four "He" nuclei completely into oxygen nuclei , then calculate energy released per oxygen nuclei in MeV . given that mass of the "He" nucleus is 4.0026 amu and mass of oxygen nucleus is 15.9994 amu .(please leave 2 cm margin from the right side while taking the picture).

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Solution

E =Δmc²
= [4×4.0026−15.9994]×
931.5
= 10.24 MeV

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Q. If a star can convert all the

H e

nuclei completely into oxygen nuclei, the energy released per oxygen nuclei is [Mass of

H e

nucleus is

4.0026 a m u

and mass of oxygen nucleus is

15.9994 a m u

]

Q. If a star can convert all the He nuclei completely into oxygen nuclei. The energy released per oxygen nuclei is [Mass of He nucleus is 4.0026 amu and mass of oxygen nucleus is 15.9994 amu]. [IIT-JEE-2005]

If a star converts all the helium $(H e)$ nuclei completely into oxygen $(O)$ nuclei, the energy released per oxygen nucleus is (mass of helium nucleus = $4.0026 a m u$ and mass of oxygen nucleus = $15.9994 a m u$ )

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If a star can convert four "He" nuclei completely into oxygen nuclei , then calculate energy released per oxygen nuclei in MeV . given that mass of the "He" nucleus is 4.0026 amu and mass of oxygen nucleus is 15.9994 amu .(please leave 2 cm margin from the right side while taking the picture).

E =Δmc² = [4×4.0026−15.9994]× 931.5 = 10.24 MeV

E =Δmc²
= [4×4.0026−15.9994]×
931.5
= 10.24 MeV